3.12.98 \(\int \frac {1}{(a-i a x)^{9/4} (a+i a x)^{7/4}} \, dx\) [1198]

Optimal. Leaf size=100 \[ -\frac {2 i}{5 a^2 (a-i a x)^{5/4} (a+i a x)^{3/4}}-\frac {8 i}{5 a^3 \sqrt [4]{a-i a x} (a+i a x)^{3/4}}+\frac {16 i (a-i a x)^{3/4}}{15 a^4 (a+i a x)^{3/4}} \]

[Out]

-2/5*I/a^2/(a-I*a*x)^(5/4)/(a+I*a*x)^(3/4)-8/5*I/a^3/(a-I*a*x)^(1/4)/(a+I*a*x)^(3/4)+16/15*I*(a-I*a*x)^(3/4)/a
^4/(a+I*a*x)^(3/4)

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Rubi [A]
time = 0.01, antiderivative size = 100, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 25, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.080, Rules used = {47, 37} \begin {gather*} \frac {16 i (a-i a x)^{3/4}}{15 a^4 (a+i a x)^{3/4}}-\frac {8 i}{5 a^3 (a+i a x)^{3/4} \sqrt [4]{a-i a x}}-\frac {2 i}{5 a^2 (a+i a x)^{3/4} (a-i a x)^{5/4}} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[1/((a - I*a*x)^(9/4)*(a + I*a*x)^(7/4)),x]

[Out]

((-2*I)/5)/(a^2*(a - I*a*x)^(5/4)*(a + I*a*x)^(3/4)) - ((8*I)/5)/(a^3*(a - I*a*x)^(1/4)*(a + I*a*x)^(3/4)) + (
((16*I)/15)*(a - I*a*x)^(3/4))/(a^4*(a + I*a*x)^(3/4))

Rule 37

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[(a + b*x)^(m + 1)*((c + d*x)^(n +
1)/((b*c - a*d)*(m + 1))), x] /; FreeQ[{a, b, c, d, m, n}, x] && NeQ[b*c - a*d, 0] && EqQ[m + n + 2, 0] && NeQ
[m, -1]

Rule 47

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[(a + b*x)^(m + 1)*((c + d*x)^(n + 1
)/((b*c - a*d)*(m + 1))), x] - Dist[d*(Simplify[m + n + 2]/((b*c - a*d)*(m + 1))), Int[(a + b*x)^Simplify[m +
1]*(c + d*x)^n, x], x] /; FreeQ[{a, b, c, d, m, n}, x] && NeQ[b*c - a*d, 0] && ILtQ[Simplify[m + n + 2], 0] &&
NeQ[m, -1] &&  !(LtQ[m, -1] && LtQ[n, -1] && (EqQ[a, 0] || (NeQ[c, 0] && LtQ[m - n, 0] && IntegerQ[n]))) && (
SumSimplerQ[m, 1] ||  !SumSimplerQ[n, 1])

Rubi steps

\begin {align*} \int \frac {1}{(a-i a x)^{9/4} (a+i a x)^{7/4}} \, dx &=-\frac {2 i}{5 a^2 (a-i a x)^{5/4} (a+i a x)^{3/4}}+\frac {4 \int \frac {1}{(a-i a x)^{5/4} (a+i a x)^{7/4}} \, dx}{5 a}\\ &=-\frac {2 i}{5 a^2 (a-i a x)^{5/4} (a+i a x)^{3/4}}-\frac {8 i}{5 a^3 \sqrt [4]{a-i a x} (a+i a x)^{3/4}}+\frac {8 \int \frac {1}{\sqrt [4]{a-i a x} (a+i a x)^{7/4}} \, dx}{5 a^2}\\ &=-\frac {2 i}{5 a^2 (a-i a x)^{5/4} (a+i a x)^{3/4}}-\frac {8 i}{5 a^3 \sqrt [4]{a-i a x} (a+i a x)^{3/4}}+\frac {16 i (a-i a x)^{3/4}}{15 a^4 (a+i a x)^{3/4}}\\ \end {align*}

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Mathematica [A]
time = 0.09, size = 52, normalized size = 0.52 \begin {gather*} \frac {2 i (a-i a x)^{3/4} \left (7+4 i x+8 x^2\right )}{15 a^4 (i+x)^2 (a+i a x)^{3/4}} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[1/((a - I*a*x)^(9/4)*(a + I*a*x)^(7/4)),x]

[Out]

(((2*I)/15)*(a - I*a*x)^(3/4)*(7 + (4*I)*x + 8*x^2))/(a^4*(I + x)^2*(a + I*a*x)^(3/4))

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Maple [A]
time = 0.15, size = 44, normalized size = 0.44

method	result	size
risch	\(\frac {\frac {16}{15} x^{2}+\frac {8}{15} i x +\frac {14}{15}}{a^{3} \left (a \left (i x +1\right )\right )^{\frac {3}{4}} \left (-a \left (i x -1\right )\right )^{\frac {1}{4}} \left (x +i\right )}\)	\(44\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(a-I*a*x)^(9/4)/(a+I*a*x)^(7/4),x,method=_RETURNVERBOSE)

[Out]

2/15/a^3/(a*(1+I*x))^(3/4)/(-a*(-1+I*x))^(1/4)*(8*x^2+4*I*x+7)/(x+I)

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Maxima [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: RuntimeError} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(a-I*a*x)^(9/4)/(a+I*a*x)^(7/4),x, algorithm="maxima")

[Out]

Exception raised: RuntimeError >> ECL says: THROW: The catch RAT-ERR is undefined.

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Fricas [A]
time = 0.61, size = 56, normalized size = 0.56 \begin {gather*} \frac {2 \, {\left (i \, a x + a\right )}^{\frac {1}{4}} {\left (-i \, a x + a\right )}^{\frac {3}{4}} {\left (8 \, x^{2} + 4 i \, x + 7\right )}}{15 \, {\left (a^{5} x^{3} + i \, a^{5} x^{2} + a^{5} x + i \, a^{5}\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(a-I*a*x)^(9/4)/(a+I*a*x)^(7/4),x, algorithm="fricas")

[Out]

2/15*(I*a*x + a)^(1/4)*(-I*a*x + a)^(3/4)*(8*x^2 + 4*I*x + 7)/(a^5*x^3 + I*a^5*x^2 + a^5*x + I*a^5)

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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {1}{\left (i a \left (x - i\right )\right )^{\frac {7}{4}} \left (- i a \left (x + i\right )\right )^{\frac {9}{4}}}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(a-I*a*x)**(9/4)/(a+I*a*x)**(7/4),x)

[Out]

Integral(1/((I*a*(x - I))**(7/4)*(-I*a*(x + I))**(9/4)), x)

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Giac [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: TypeError} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(a-I*a*x)^(9/4)/(a+I*a*x)^(7/4),x, algorithm="giac")

[Out]

Exception raised: TypeError >> An error occurred running a Giac command:INPUT:sage2:=int(sage0,sageVARx):;OUTP
UT:ext_reduce Error: Bad Argument TypeDone

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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {1}{{\left (a-a\,x\,1{}\mathrm {i}\right )}^{9/4}\,{\left (a+a\,x\,1{}\mathrm {i}\right )}^{7/4}} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/((a - a*x*1i)^(9/4)*(a + a*x*1i)^(7/4)),x)

[Out]

int(1/((a - a*x*1i)^(9/4)*(a + a*x*1i)^(7/4)), x)

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